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Relax 2025-02-08 17:53:37

Check answer 👉:

Let’s solve this step by step:

  1. First equation:

    Shoes+Shoes+Shoes=30\text{Shoes} + \text{Shoes} + \text{Shoes} = 30

    This implies each pair of shoes is 1010:

    10+10+10=3010 + 10 + 10 = 30

  2. Second equation:

    Boy+Boy+Shoes=20\text{Boy} + \text{Boy} + \text{Shoes} = 20

    Since the shoes are 1010, we have:

    2Ă—Boy+10=202 \times \text{Boy} + 10 = 20

    Solving for the boy:

    2×Boy=10⇒Boy=52 \times \text{Boy} = 10 \Rightarrow \text{Boy} = 5

  3. Third equation:

    Burger+Burger+Boy=13\text{Burger} + \text{Burger} + \text{Boy} = 13

    We know the boy is 55, so:

    2Ă—Burger+5=132 \times \text{Burger} + 5 = 13

    Solving for the burger:

    2×Burger=8⇒Burger=42 \times \text{Burger} = 8 \Rightarrow \text{Burger} = 4

  4. Final equation:

    Shoe+(Boy with two small burgers)×Burger=?\text{Shoe} + (\text{Boy with two small burgers}) \times \text{Burger} = ?
    • A single shoe is half of a pair, so it’s 55.
    • The boy with two small burgers should represent 5+2=75 + 2 = 7.
    • The burger is 44.

    Now, substitute into the equation:

    5+(7Ă—4)=5+28=335 + (7 \times 4) = 5 + 28 = 33

Answer: 33

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