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1 day before

Check answer 👉:

Let’s solve this step by step:

First equation:

Shoes+Shoes+Shoes=30\text{Shoes} + \text{Shoes} + \text{Shoes} = 30

This implies each pair of shoes is 1010:

10+10+10=3010 + 10 + 10 = 30

Second equation:

Boy+Boy+Shoes=20\text{Boy} + \text{Boy} + \text{Shoes} = 20

Since the shoes are 1010, we have:

2×Boy+10=202 \times \text{Boy} + 10 = 20

Solving for the boy:

2×Boy=10⇒Boy=52 \times \text{Boy} = 10 \Rightarrow \text{Boy} = 5

Third equation:

Burger+Burger+Boy=13\text{Burger} + \text{Burger} + \text{Boy} = 13

We know the boy is 55, so:

2×Burger+5=132 \times \text{Burger} + 5 = 13

Solving for the burger:

2×Burger=8⇒Burger=42 \times \text{Burger} = 8 \Rightarrow \text{Burger} = 4

Final equation:

Shoe+(Boy with two small burgers)×Burger=?\text{Shoe} + (\text{Boy with two small burgers}) \times \text{Burger} = ? A single shoe is half of a pair, so it’s 55. The boy with two small burgers should represent 5+2=75 + 2 = 7. The burger is 44.

Now, substitute into the equation:

5+(7×4)=5+28=335 + (7 \times 4) = 5 + 28 = 33

Answer: 33

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